#abc079b. [abc079_b]Lucas Number

[abc079_b]Lucas Number

Problem Statement

It is November 1818 now in Japan. By the way, 1111 and 1818 are adjacent Lucas numbers.

You are given an integer NN. Find the NN-th Lucas number.

Here, the ii-th Lucas number LiL_i is defined as follows:

  • L0=2L_0=2
  • L1=1L_1=1
  • Li=Li1+Li2(i2)L_i=L_{i-1}+L_{i-2} (i≥2)

Constraints

  • 1N861≤N≤86
  • It is guaranteed that the answer is less than 101810^{18}.
  • NN is an integer.

Input

Input is given from Standard Input in the following format:

NN

Output

Print the NN-th Lucas number.


Sample Input 1

5

Sample Output 1

11
  • L0=2L_0=2
  • L1=1L_1=1
  • L2=L0+L1=3L_2=L_0+L_1=3
  • L3=L1+L2=4L_3=L_1+L_2=4
  • L4=L2+L3=7L_4=L_2+L_3=7
  • L5=L3+L4=11L_5=L_3+L_4=11

Thus, the 55-th Lucas number is 1111.


Sample Input 2

86

Sample Output 2

939587134549734843