Problem Statement

We have an empty box.
Takahashi can cast the following two spells any number of times in any order.

• Spell $A$: puts one new ball into the box.
• Spell $B$: doubles the number of balls in the box.

Tell us a way to have exactly $N$ balls in the box with at most $\\mathbf{120}$ casts of spells.
It can be proved that there always exists such a way under the Constraints given.

There is no way other than spells to alter the number of balls in the box.

Constraints

• $1 \\leq N \\leq 10^{18}$
• All values in input are integers.

Input

Input is given from Standard Input in the following format:

$N$

Output

Print a string $S$ consisting of A and B. The $i$-th character of $S$ should represent the spell for the $i$-th cast.

$S$ must have at most $\\mathbf{120}$ characters.

Sample Input 1

5

Sample Output 1

AABA

This changes the number of balls as follows: $0 \\xrightarrow{A} 1\\xrightarrow{A} 2 \\xrightarrow{B}4\\xrightarrow{A} 5$.
There are also other acceptable outputs, such as AAAAA.

Sample Input 2

14

Sample Output 2

BBABBAAAB

This changes the number of balls as follows: $0 \\xrightarrow{B} 0 \\xrightarrow{B} 0 \\xrightarrow{A}1 \\xrightarrow{B} 2 \\xrightarrow{B} 4 \\xrightarrow{A}5 \\xrightarrow{A}6 \\xrightarrow{A} 7 \\xrightarrow{B}14$.
It is not required to minimize the length of $S$.